Solve for b -7+3b=4b-8

$- 7 + 3 b = 4 b - 8$

Move all terms containing $b$ to the left side of the equation.

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Subtract $4 b$ from both sides of the equation.

$- 7 + 3 b - 4 b = - 8$

Subtract $4 b$ from $3 b$ .

$- 7 - b = - 8$

Move all terms not containing $b$ to the right side of the equation.

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Add $7$ to both sides of the equation.

$- b = - 8 + 7$

Add $- 8$ and $7$ .

$- b = - 1$

Multiply each term in $- b = - 1$ by $- 1$

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Multiply each term in $- b = - 1$ by $- 1$ .

$(- b) \cdot - 1 = (- 1) \cdot - 1$

Multiply $(- b) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 b = (- 1) \cdot - 1$

Multiply $b$ by $1$ .

$b = (- 1) \cdot - 1$

Multiply $- 1$ by $- 1$ .

$b = 1$

Solve for b -7+3b=4b-8